What happens to the resistance when area is halved?

When the area of cross section is halved then resistance becomes double .

What happens to the resistance if the radius of the wire is constant and radius is doubled?

(b) Resistance of a wire is inversely proportional to the area of cross-section the wire. Thus, if radius is doubled, area increases four times and hence the resistance becomes one-fourth.

What happens to the resistance of the wire?

The relationship between resistance and wire length is proportional . The resistance of a thin wire is greater than the resistance of a thick wire because a thin wire has fewer electrons to carry the current. The relationship between resistance and the area of the cross section of a wire is inversely proportional .

What happens to resistance of a conductor if area of cross section is halved?

This is because resistance is inversely proportional to area.

What happens to the resistance of a wire when?

So we know that cross-sectional area is directly proportional to the radius of the wire. Therefore, if the cross-sectional area decreases, the resistance will increase.

What happened to resistance of an electric circuit if I the diameter of the conductor wire gets doubled if radius of conductor wire gets half?

From this relation we can conclude that resistance is inversely proportional to area A of the conductor. Area of the conductor becomes 4 times the area of the conductor without doubling the diameter. Thus, we can say that new resistance will decrease four times.

How does the resistance of a wire will change if the current is reduced to half?

According to the question, Resistance of wire gets halved then heating effect also gets affected. So according to this relation heating effect of current is inversely proportional to resistance.

What is the relationship between the resistance of a wire and its radius?

However, the cross-sectional area of the wire is proportional to the square of the radius of the wire. This means that the resistance of the wire and radius of the wire is inversely proportional to each other. Therefore, as the radius increases, the resistance of wire decreases.

What would be the new resistance if length of a conductor is halved and thickness is doubled?

If you halve the ‘thickness’ of a circular conductor, the cross-sectional area (CSA) will be one quarter of what it was. This means that the resistance will increase by a factor of 4 (X4). If you now double its length, the resistance will only double (X2). Overall, the resistance will be 8 times what it was.

Why does the resistance of a metallic conductor increases with temperature?

The resistance of a conductor increases with an increase in temperature because the thermal velocity of the free electrons increases as the temperature increases. This results in an increase in the number of collisions between the free electrons.

How is the resistance of a wire affected when diameter is doubled?

Because when diameter will large then the area of cross section will large and electrons can move more freely hence the resistance wiil reduce. How is the resistance of wire affected if its length is doubled radius is doubled? When the radius of the wire is doubled it means the area of cross-section is increased by four times.

What is the resistance of a half-led wire?

Resistance of wire depends upon resistivity, length and area of cross section,in simple words resistance is directly proportional to lenght and inversely proportional to cross sectional area. In this case since lenght is halfed and area is doubled resistance decreases by 4 times.

What happens if length is doubled and radius is halved?

If length is doubled and radius is halved the resistance would increase by 8 times. Since R = P* L/A: since resistivity is constant, Length becomes 2L and area becomes 1/4 th. Therefore it is 8 times.

How does the resistance vary if the length of a conductor?

How does the resistance vary if the length of a conductor is doubled? If the length is double then the resistance would increase by 8 times. Since R=P*L/A (Resistivity constant) length becomes 2L and area becomes 1/4th. So, almost the new resistance increase by 4 times.