At what height from earth gravity becomes g 2?

Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s2….The Value of g Depends on Location.

Location	Distance from Earth’s center (m)	Value of g (m/s2)
50000 km above surface	5.64 x 107 m	0.13

At what height above the surface of earth the value of acceleration due to gravity is reduced to one fourth of its value on the surface of the earth?

At what height above the earth’s surface would the acceleration due to gravity be (i) half, (ii) one-fourth of its value at the earth’s surface? (Radius of earth = 6400 km). Ans. (i) 2650 km, (ii) 6400 km.

Is the radius of the earth shrinks by 2\% mass remaining constant then how would the value of acceleration due to gravity change?

Hence the value of acceleration due to gravity change by 4\%.

At what height from surface of Earth the value of acceleration due to gravity will become half that on the surface of the earth RE 6400 km?

If we use 6,371 km as Earth’s radius, the distance above the surface where gravitational acceleration is halved would be 2,639 km. Note: Gravitational acceleration is an object’s free fall motion under space — with no friction.

What is the acceleration due to gravity at height h?

As altitude or height h increases above the earth’s surface the value of acceleration due to gravity falls. This is expressed by the formula g1 = g (1 – 2h/R). Here g1 is the acceleration due to gravity at height h and R is the radius of the earth.

Does gravity increase with height on Earth?

From surface of the Earth … yes. Generally… for height h, the acceleration due to gravity is: a = GM/(R+h)^2 … so it decreases with height. This is because the Earth is basically a ball. This result applies for all objects that are basically ball-shaped.

How acceleration due to gravity changes with depth from Earth’s surface?

Variation of g with depth or How Acceleration due to gravity changes with depth from the earth’s surface? As depth h increases below the earth’s surface the value of acceleration due to gravity falls. This is expressed by the formula g2 = g (1 – h/R). Here g2 is the acceleration due to gravity at depth h and R is the radius of the earth.

What is the change in the value of G with height?

So as altitude h increases, the value of acceleration due to gravity falls. This describes the variation of g with height or altitude. What is the change in the value of g at a height h? g1 = g (1 – 2h/R) This g1 gives the formula for g at height h. So the value of g will decrease by this amount: 2hg/R, at a height h above the earth’s surface.