At what time between 4 and 5 o clock will the hands of a watch point in opposite directions?

4 o’clock, the hands of the watch are 20 min. spaces apart. To be in opposite directions, they must be 30 min.

At what time between 4 and 5 o’clock the hands of clock will be together?

Let the hands of the clock coincide after x minutes. So, the hands of a clock coincide $21.81$ minutes past 4. Therefore, the correct answer is option B, 21.81 min.

At what time between 4 and 5 o’clock are the hands of the clock at right angles for the first time?

Description for Correct answer: Between 4 and 5 o ‘clock the hands of the clock will be at right angle once. When the two hands are at right angles, they are 15 minutes space apart. When the minutes hand is 15 minute space ahead of the hour hand.

How many times do hands of a clock coincide in 5 hours a 5 B 4 C 11 D 12?

The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they coincide only once, i.e., at 12 o’clock). The hands overlap about every 65 minutes, not every 60 minutes. The hands coincide 22 times in a day….

Now,	34	min. are gained in 170 hrs.
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What time will the hands of a watch point in opposite directions?

At what time between 4 and 5 o’clock will the hands of a watch point in opposite directions? At 4 o’clock, the hands of the watch are 20 min. spaces apart. To be in opposite directions, they must be 30 min. spaces apart. ∴ Minute hand will have to gain 50 min. spaces.

How far apart should hands of 4 o’clock watch be?

At 4 o’clock, the hands of the watch are 20min. spaces apart. To he in opposite directions, they must be 30 min. spaces apart. ∴ Minute hand will have to gain 50min. spaces. 55min. spaces are gained in 60min.

How do you calculate the time on a 4 o clock?

Initial angle between the two at 4 ‘O’ clock is 4* 30 = 120 degree. The minute hand has to move 120 +180 = 300 degree to have required position. Hence the time is 4 hour 54 minutes and 33 seconds. The minute hand travels 6m° in m minutes and hour hand travels (4×60 + m)x½ = (120 + m/2)° Required time is 4:54:33 becoz it can’t be negative.

Will the hands of a clock be in a straight line?

Solution: At 1:x. 2:y and 3:z will the hands of a clock be in a straight line but in opposite directions. Now to find, x, y and z. So, at 1:38:10.91 the hands of a clock be in a straight line but in opposite directions. So, at 2:43:38.18 the hands of a clock be in a straight line but in opposite directions.