How do you find the altitude of a satellite?
Table of Contents
- 1 How do you find the altitude of a satellite?
- 2 How high up would such a satellite need to be in order to orbit exactly once a day?
- 3 What is the height of the satellite above the surface of the earth?
- 4 What height must a satellite be placed above the surface of the Earth in order for its rotation?
- 5 How do you find the height of a satellite above the Earth?
- 6 How do you calculate the gravitational force between Earth and satellites?
- 7 What is the apogee altitude of a satellite in Earth orbit?
How do you find the altitude of a satellite?
To find altitude, subtract the radius of Mars from this number. Remember to always use the distance from the core of the planet in these calculations! The satellite in Mars geostationary orbit must be stationed 17005 Kilometers above the surface of the planet and it must be travelling at a speed of 1446 m/s .
How high up would such a satellite need to be in order to orbit exactly once a day?
A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day.
How far from the center of the earth does a satellite to be to have an orbital period of 4 days?
4. Consider a satellite which is in a low orbit about the Earth at an altitude of 220 km above Earth’s surface. Determine the orbital speed of this satellite. Use the information given below….Mathematics of Satellite Motion.
| Sun | M = 2.0 x 1030 kg |
|---|---|
| Earth | M = 6.0 x 1024 kg |
| Saturn | M = 5.7 x 1026 kg |
What is the height of the satellite above the surface of the earth?
Geostationary orbit A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level. It maintains the same position relative to the Earth’s surface.
What height must a satellite be placed above the surface of the Earth in order for its rotation?
In order to perfectly match Earth’s rotation, the speed of GEO satellites should be about 3 km per second at an altitude of 35 786 km.
How do you find the period of revolution of a satellite?
Given: r1 = R + 6R = 7R, r2 = R + 2.5 R = 3.5 R, Time period of geostationary satellite T1 = 24 hours. To Find: Period of second satellite T2 =? Ans: The period of revolution of a satellite orbiting at a height of 2.5 R above the earth’s surface is 8.458 hr.
How do you find the height of a satellite above the Earth?
T = 5176 s = 1.44 hrs. The solution then involves first finding the radius of orbit and using this R value and the R of the earth to find the height of the satellite above the earth. As shown in the diagram at the right, the radius of orbit for a satellite is equal to the sum of the earth’s radius and the height above the earth.
How do you calculate the gravitational force between Earth and satellites?
The gravitational force between the satellite and the Earth is in the radial direction and its magnitude is given by the Newton’s equation F = GMm/r 2 (1) where G is the gravitational constant, M and m are the masses of the Earth and the satellite respectively and r is the radius of the orbit.
What is the formula for calculating the velocity of a satellite?
v2 = (G • MCentral) / R Taking the square root of each side, leaves the following equation for the velocity of a satellite moving about a central body in circular motion where G is 6.673 x 10 -11 N•m 2 /kg 2, Mcentral is the mass of the central body about which the satellite orbits, and R is the radius of orbit for the satellite.
What is the apogee altitude of a satellite in Earth orbit?
A satellite in Earth orbit passes through its perigee point at an altitude of 200 km above the Earth’s surface and at a velocity of 7,850 m/s. Calculate the apogee altitude of the satellite.