How do you find the equation of a circle given the center and tangent to the y axis?

Correct answer: The formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

What is the equation of a circle whose center is at (- 4 3 and is tangent to circle?

Correct answer: Explanation: The graph of the equation \displaystyle x^{2}+ y^{2} = 225 is a circle with center . \displaystyle \frac{ y_{2} – y_{1} }{x_{2} – x_{1} } =\frac{-9 -0}{12-0} =\frac{-9 }{12 }=- \frac{3}{4}, so the tangent line has the opposite of the reciprocal of this, or , as its slope.

What is the equation of a circle whose center is at point (- 4 6 and passes through the point 1/2 )?

Centre is (1, 2) and which passes through the point (4, 6). We need to find the equation of the circle. x2 + y2 – 2x – 4y – 20 = 0. ∴ The equation of the circle is x2 + y2 – 2x – 4y – 20 = 0.

What is the center of a circle whose equation is x2 y2 12x 2y 12 0?

The center of the circle of the given equation is x2 + y2 – 12x – 2y + 12 = 0 is (6,1).

What is the equation of the circle with center − 1 − 2 and passes through the point 6 4 )? Which of the following points is also located on the circle?

The distance from (1,2) to (4,6) = sqrt[(4-1)2 + (6-2)2] = 5 and this is the radius of the circle. The equation of the circle is (x-1)2 + (y-2)2 = 25.

How to find the tangent of a circle to the Y-axis?

The equation for a circle is (x −h)2 + (y −k)2 = r2, where (h,k) is the center and r is the radius. Since you want the circle to be tangent to the y -axis, and we know that tangent refers to a line that touches something at exactly one point, we want the circle to have a radius that will make it just big enough to reach the y -axis.

How do you find the equation of a circle with center?

The equation of circle with (h,k) center and r radius is given by: (x-h) 2 + (y-k) 2 = r 2. Thus, if we know the coordinates of the center of the circle and its radius as well, we can easily find its equation. Example: Say point (1,2) is the center of the circle and radius is equal to 4

What is the equation for a circle with a radius of 3?

A radius of 3, since the x -value of the center is at h = 3, will just make the circle the right size to touch the y -axis. Plug 3 in for r, and you get the final equation: (x −3)2 + (y +7)2 = 9

What is the radius of the circle above the x axis?

Because the center is 2 units above the x axis and the circle is tangent to the x axis, the radius must be 2: (x −4)2 + (y −2)2 = 22