How does the resistance of a wire change when the length is decreased?

The relationship between resistance and wire length is proportional . The resistance of a thin wire is greater than the resistance of a thick wire because a thin wire has fewer electrons to carry the current. The relationship between resistance and the area of the cross section of a wire is inversely proportional .

What happens to the resistivity of a wire if it’s length is reduced to half?

Since resistance is directly proportional to the length of the conductor, hence, in this case the resistance will decrease to half.

What will be the change in the value of resistance if length of a conductor and its radius is doubled?

(a) Resistance of a wire is directly proportional to the length of a wire; so if the length is doubled, resistance is also doubled. Thus, if radius is doubled, area increases four times and hence the resistance becomes one-fourth.

How does length affect resistance?

First, the total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be. After all, if resistance occurs as the result of collisions between charge carriers and the atoms of the wire, then there is likely to be more collisions in a longer wire.

What will happen to resistance if the length of the what will happen to resistance if the length of the conductor is increased conductor is increased?

the resistance of a conductor is directly proportional to its length. so if length is increased then resistivity increases ande vice versa. so if length is doubled resistance will also get doubled i.e resistance is 4 times that of original resistance.

What will happen to resistance if length increases?

From the equation, we understand that resistance is directly proportional to the length of the conductor and inversely proportional to the crossectional area of the conductor. Doubling the length doubles the resistance.

What will happen to resistance if the length of the conductor is increased?

This is how the resistance of a conductor changes, depending on the conductor’s length. Increased conductor length equals increased resistance in direct proportion. The thinner or smaller the diameter (cross sectional area), the greater the resistance.

What will happen if the length of the conductor is doubled and the area of cross section remains the same?

Initial length of the conductor l1=l Final length of the conductor l2=2l Initial cross-sectional area A1=A Final cross-sectional area A2=2A The resistance of conductors given by R=ρ1A∝1A As both the length and area are doubled Hence, there will be no change in the resistance of the conductor and so it will remain …

What happens to the resistance of A wire when its length is increased to twice its original length?

resistance is directly proportional to length, so resistance will also become twice.

When the length of the wire gets doubled what will be the change in current?

If the length of the wire is doubled then the resistance of the wire will also double. Hence, the Current will decrease to one half.

How will the resistance of a wire change when?

How will the resistance of a wire change when : Its length is doubled. Resistance of wire is proportional to length and inversely proportional to area. Volume of wire is always constant. ⇒ Area is halved.

What happens when the length of a wire is doubled?

From this relation, we observe that the length is directly proportional to the resistance and the area of cross section is inversely proportional to the resistance. . So, R = 2R’. Hence, If the length of a wire is doubled, then its resistance becomes 2 times.

How do you calculate the resistance of a 2L wire?

Thus when one computes the new resistance using R=Rho*length/Area, and plugs in the new values for length = 2L and radius=R/sqrt (2), the new resistance value end up being 4R (where R is the resistance of the original length wire). Hope this helps. A wire has a resistance of 10 ohms.

What is the radius of a longer wire?

When we double the length of the wire (100\% increase) – the radius decreases – this is such that the volume of the metal remains the same. It turns out that in this particular case, the new radius of the longer wire is R/sqrt (2).