How many 2 digit positive integers are there with the property that the sum of the integers digits equals the product of those digits?

if 3 · 8 = 24 , then sure enough 8 · 3 = 24 too. So for the two pairs of integers ( 3 and 8 , along with 4 and 6 ), the two-digit positive integers whose product of their digits is 24 are: 38 , 83 , 46 , and 64 . Since we have four different two-digit integers, the correct answer is C, Four.

How many different two-digit positive integers are there in which the tens digit is greater that 6 and unit digit is greater than 4?

The question wants numbers which their tens digit is more than 6, Thus their tens digit can be 7, 8 and 9. Units digit is the digit with power 0, in 17: unit digit is 7, in 68: unit digit is 8. Unit digit must be less than 4, So it can be 0, 1, 2, 3. there are 12 numbers with these circumstances.

How many two-digit positive integers are there such that the product of the two digits is 24?

There are four 2-digit positive integers whose product of the two digits is 24 (38, 46, 64, and 83).

How many two-digit positive integers are there?

There are 20 positive, two-digit numbers that meet the requirements. They are: 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, 99. There are 20 integers which meet these criteria. Not including single-digit integers prefixed with a 0, there are 90 possible two-digit integers.

How many 2-digit positive perfect squares are there?

So, there are 17 two-digit numbers whose sum of digits is a perfect square. Note: Perfect squares are those numbers which are formed when any number is multiplied by itself.

How many positive two digit monotonic integers are there?

Then as there is one decreasing monotonous number for every increasing monotonous number, I multiplied it by 2 to get 90 total 2-digit monotonous numbers.

How many different 2 digit numbers are there?

The total number of two digit numbers is 90. From 1 to 99 there are 99 numbers, out of which there are 9 one-digit numbers, i.e., 1, 2, 3, 4, 5, 6, 7, 8 and 9.

How many two digit positive integers consists of distinct odd digits?

There are 4 of them. 2-digit integers: 10, 12., 98 (45 of these), but in 4 of them (22, 44, 66, 88) the two digits are the same. So there are 45 − 4 = 41 even 2-digit integers with distinct digits. Here is another way to think about this part: the first digit can be odd or even.

How many two-digit positive integers are divisible by the sum of the number’s digits?

Hence we conclude that the only 2-digit positive integers which are divisible by both the sum and product of their digits are 12, 24, and 36.

What are the integers of 24?

So, the three consecutive integers whose sum is 24 are 7, 8 and 9.

How many two digit positive integers and have the property that the sum of n and the number obtained by reversing the order of the digits of N is a perfect square?

There are 8 integers who have the property.

How many two-digit positive integers whose product of their digits is 24$?

So for the two pairs of integers ($3$ and $8$, along with $4$ and $6$), the two-digit positive integers whose product of their digits is $24$ are: $38, 83, 46, \\and 64$. Since we have four different two-digit integers, the correct answer is C, Four.

How do you find the number of positive integers with digit sum?

When n = 1 n = 1, we have 2 2 such numbers: 01,10 01, 10. When n= 2 n = 2, we have 3 3 such numbers: 02,11,20 02, 11, 20. When n= 3 n = 3, we have 4 4 such numbers: 03,12,21,30 03, 12, 21, 30. And so on… We can see that every time n n increases by 1 1, the number of positive integers with digit sum equal to n n also increases by 1 1.

How to write positive integers less than 100 as two-digit numbers?

It helps to write all positive integers less than 100 100 as two-digit numbers, where the first digit could be 0 0. These are 9 9 such integers: 08,17,26,35,44,53,62,71,80 08, 17, 26, 35, 44, 53, 62, 71, 80. Let n n be a positive integer with n< 10 n < 10.

How many two digit positive integers have a tens digit greater than 6?

If you read the stem step by step very carefully the solution is pretty quick. different two-digit positive integers are there in which the tens digit is greater than 6 = 7,8,9 units digit is less than 4 = 0,1,2,3. For istance: 70,71,72, 73.