FAQ

How many 5 digit numbers formed using the digits 0 1 2 3 4 5 are divisible by 3 if digits are not repeated?

How many 5 digit numbers formed using the digits 0 1 2 3 4 5 are divisible by 3 if digits are not repeated?

Sum of the digits = 0 + 1 + 2 + 3 + 4 = 10 which is not divisible by 3. ∴ None of the 5-digit numbers formed using the digits 0, 1, 2, 3, and 4 will not be divisible by 3.

What is the place value of a 5 digit number?

When we see a 5-digit number, the five digits will correspond to the 5 place values – Units, Tens, Hundreds, Thousands, and Ten Thousand.

How many 5 digit numbers are there in all solution?

90,000 numbers
Question 12 Q7)How many 5-digit numbers are there in all? So, 90,000 numbers are there in all.

READ ALSO:   How do I find out if I paid stamp duty?

How many possible 5-digit numbers are there?

The smallest 5 5 -digit number is 10000, 10000, while the largest 5 5 -digit number is 99999. 99999. These 90000 90000 possible 5 5 -digit numbers can have any number from 0 0 to 9 9 in any of the places, except for the placement of zero such that there is no non-zero number to its left.

How do you find the place value of a 5 digit number?

The place value of the five digits that make up the 5-digit number would be obtained by progressively multiplying the respective figure by 1, 10, 100, 1,000, and 10,000 starting from the rightmost digit and moving to the left. As shown above, is a 5-digit number, every progressive place value is the earlier place value multiplied by 10.

How do you write 20340 as a five-digit number?

Let us continue with the same number 20340. 2 is in Ten Thousands place = 2 × 10000 = 20000. 0 is in Thousands place = 0 × 1000 = 0. 3 is in Hundreds place = 3 × 100 = 300. 4 is in Tens place = 4 × 10 = 40. 0 is in Units place = 0 × 1 = 0. Hence, the five-digit number can be expressed in the following way: 20000 + 0 + 300 + 40 + 0 = 20340 .

READ ALSO:   Why is my iPhone 7 battery suddenly draining so fast after update?

How to place a random 5-digit number on an abacus?

The given figure shows how a random 5-digit number is placed on an abacus. The place value of the five digits that make up the 5-digit number would be obtained by progressively multiplying the respective figure by 1, 10, 100, 1,000, and 10,000 starting from the rightmost digit and moving to the left.