How many address bits are needed to operated a 8k 8 ROM?

So, therefore we need an additional 3 address bits to increase this by a factor of 8 (8 = 2 cubed), giving a total of 13 address bits.

How many unique addresses would be required to access 2 to the 16 memory cells?

So 2 to the power of 16 is 65,536, commonly referred to as 64K. The number of memory words addressed on a bus is 2 to the power of the width of the address bus, in this case 16. So 2 to the power of 16 is 65,536, commonly referred to as 64K.

How many 128 16 RAM chips are needed to provide?

Answer: 16K bytes = 16 x 1024 x 8 => 128 chips.

How many chips are needed to provide a memory capacity of 16 K bytes of a computer uses RAM chips of 1024 1 capacity?

A RAM chip has a capacity of 1024 words of 8 bits each. The number of 2- to-4 decoders with enable lines needed to construct a 16K x 16 RAM system will be ………………….. Correct answer is 5. To construct a memory system with 16K words using 1024×8 RAM chips, we have to connect 16 such chips in parallel.

How many separate address and data lines are needed for a memory of 16k 16?

1 comment. 8K∗16=213∗16, thus 13 address lines and 16 data lines.

What is 8K memory?

RAM with 8K memory can store 8192 bytes or 65536 bits. Therefore : 8192 bytes = 8 * 8192 bits =65536 bits.

How many chips are needed to provide a memory capacity of 16 K bytes if a computer uses RAM chips of 1kx8 capacity?

Explanation: RAM chip size = 1k ×8[1024 words of 8 bits each] RAM to construct =16k ×16 Number of chips required = (16k x 16)/ ( 1k x 8) = (16 x 2) [16 chips vertically with each having 2 chips horizontally] So to select one chip out of 16 vertical chips, we need 4 x 16 decoder.

How many 1kb IC’s are required to build 1mb memory?

Answer: A total of 32 RAM chips are needed to build 1 MB of memory. = 32 chips. Thus, 32 RAM chips are needed to build 1 MB of memory.

How many memory locations can be accessed with a 16 bit address bus?

A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.

How many addresses and data lines will be there for a 16M * 32 memory system?

How many address and data lines will be there for a 16M x 32 memory system? d. None of the above Correct solution is (c). Since there are 16M words, the number of address lines will be 24, since 224 = 16M.

How many chips are required to construct a 16K×16 chip?

Explanation: RAM chip size = 1k ×8 [1024 words of 8 bits each] RAM to construct =16k ×16 Number of chips required = (16k x 16)/ (1k x 8) = (16 x 2) [16 chips vertically with each having 2 chips horizontally] So to select one chip out of 16 vertical chips, we need 4 x 16 decoder.

What is the size of a 16k RAM chip?

RAM chip size = 1k ×8 [1024 words of 8 bits each] RAM to construct =16k ×16 Number of chips required = (16k x 16)/ ( 1k x 8) = (16 x 2) [16 chips vertically with each having 2 chips horizontally] So to select one chip out of 16 vertical chips, we need 4 x 16 decoder.

How to represent 64K x 8 with 16K x 1 memory?

In order to represent 64K x 8 with 16K x 1, we will require 8 columns and 4 rows each of 16K x 1 memory chip. Each chip has a control input CS. When this input is set to 1, it enables that chip to accept that data input or to place the data on its output line.

How many address lines are there in a 16Kx1 memory chip?

Usually the memory chips have both the address lines (14 in the case of 16kx1 chips) plus at least one CE (chip enable line). You will connect the same 14 lowest address line bits to the chips as address lines. Just make sure your decoding logic only enables one chip bank at a time.

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