How many combinations can you get with 12 numbers?

4,095
The number of possible combinations with a 12-digit number is 4,095.

How many different ways can you make 12?

There are 89 ways (and 89 is the 11th Fibonacci number). You’re looking for “restricted compositions” of 12 (the restriction being that each part is at least 2).

How many possible combinations can you make with 3 numbers?

There are exactly 1,000 possible combinations for a 3-digit code. There are 10,000 combinations possible for a 4-digit code.

What is the combination of 12?

This number is called “twelve factorial” and written 12!, so, for example 4!= 4x3x2x1=24. These 479001600 “strings” of the 12 numbers, for example 1,2,3,4,5,6,7,8,9,10,11,12 and 2,4,6,8,10,12,11,9,7,5,3,1, mathematicians call permutations of the 12 numbers rather than combinations.

What can make 12?

The factors of 12 are 1, 2, 3, 4, 6, and 12, because each of those divides 12 without leaving a remainder (or, alternatively, each of those is a counting number that can be multiplied by another counting number to make 12).

How many possible combinations can you make with 12 different balls?

If you choose only one element r = 1 at once from that set, the number of combinations will be 12 – because there are 12 different balls. However, if you choose r = 12 elements, there’ll be only 1 possible combination that includes every ball. Try it by yourself with the n choose r calculator!

How do you calculate the number of combinations with repetition?

Explanation of the formula – the number of combinations with repetition is equal to the number of locations of n − 1 separators on n-1 + k places. A typical example is: we go to the store to buy 6 chocolates. They offer only 3 species. How many options do we have? k = 6, n = 3.

How many combinations can you make with only one element?

You may notice that, according to the combinations formula, the number of combinations for choosing only one element is simply n. On the other hand, if you have to select all the elements, there is only one way to do it. Let’s check this combination property with our example. You’ve got the total number of objects that equals n = 12.

What is the total number of ways with and without repetition?

SO, the total numbers with repetition will be: 3 x 8 x 8 x 8 = 3 x 512 = 1536 ways. The first place can be filled by again 2,3 and 4. The remaining three places can be filled by 7 x 6 x 5 = 210 way. So, the total number of ways will be without repetition will be: 3 x 7 x 6 x 5 = 630 ways.