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How many different arrangements can be made from the letters of the word BANANA?

How many different arrangements can be made from the letters of the word BANANA?

B – 1 A – 3 N – 2 So total no of words possible is factorial(6) ie 6! but we must remove duplicate words: ie- (6!/(2!* 3!)) which gives 60 So 60 distinguishable permutation of the letters in BANANA.

How many arrangements are there of the letters in BANANA such that the letter B is followed by an A ‘? *?

Total # of arrangements of BANANA is 6!/(3! 2!) = 60 (arrangement of 6 letters {B}, {A}, {N}, {A}, {N}, {A}, where 3 A’s and 2 N’s are identical). The # of arrangements in which the two N’s ARE together is 5!/3!=

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How many ways can the letters of the word BANANA be rearranged such that the new word does not begin with AB?

allocations of ANANA. Hence the solution is 5!

How many different arrangements can be made out of the letters of the word engineering?

Therefore, in 277200 ways the word ENGINEERING can be arranged without repetition of letters.

How many arrangements can be made with the letters of the word calculator in how many of these arrangements vowels occur together?

Assuming all vowels will be together 15,120 arrangements.

How many arrangements can be formed out of letters of the word Calcutta?

=5040. The geometric mean and harmonic mean of two non-negative observations are 10 and 8 respectively.

How many arrangements can made out of the letters of the word mathematics?

The word MATHEMATICS consists of 2 M’s, 2 A’s, 2 T’s, 1 H, 1 E, 1 I, 1 C and 1 S. Therefore, a total of 4989600 words can be formed using all the letters of the word MATHEMATICS.

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How many arrangements of the letters of the word banana are there?

The number of arrangements of the letters of the word BANANA in which the two N’s do not appear adjacently, is – Sarthaks eConnect | Largest Online Education Community The number of arrangements of the letters of the word BANANA in which the two N’s do not appear adjacently, is (a) 40 (b) 60 (c) 80 (d) 100

How many possible arrangements of the word economics are there?

Let us first find the total number of possible arrangements without any condition. So required number of total arrangements = 60 – 20 = 40 arrangements. Number of ways in which the letters of the word economics be arranged so that no two similar letters are together is? It is to be noted that letter ‘C’ and ‘O’ are repeated twice.

How many 2C’s and 2OS are present where both are always together?

Note the above arrangement shows that 2C’s and 2M’s are always together. This arrangement shows that 2C’s are always together. Now under this condition there is chances that Both 2Cs and 2Os are together. So Already calculated that 5040 such arrangements are present where both 2Cs and 2Os are together.