How many five digit numbers are divisible by 3?

Five digit number divisible by 3 is formed using 0, 1, 2, 3, 4, 6 and 7 without repetition. Total number of such numbers are Five digit number divisible by 3 is formed using 0, 1, 2, 3, 4, 6 and 7 without repetition.

What is the total number of choices for the first digit?

For the third number, there are 4 choices, for the fourth number there are 3 choices, and for the fifth number there are 2 choices. Thus, the total number of choices is (5) (5) (4) (3) (2) = 600. Alternatively, use the same logic and realize there are 5 choices for the first digit.

What is the first and second digit of a 5 digit number?

For the first digit, there are only five options (5, 6, 7, 8, and 9) because a five-digit number must start with a non-zero integer. For the second digit, there are 5 choices again, because now zero can be used but one of the other numbers has already been used, and numbers cannot be repeated.

What is the divisibility rule for 5 digit prime numbers?

Given: A 5 digit number using 1, 2, 3, 4 and 5 without repetition. Concept used: A prime number is a number that can be divided exactly only by itself(example – 2, 3, 5, 7, 11 etc.) So, we will use the divisibility rule.

How do you find a number divisible by 6?

For a number to be divisible by 6, it should have both 2 and 3 as factors. Quantitative Aptitude – Modern Maths – P&C – Q1: In how many ways can 8 identical pens be distributed among Amal, Bimal, and Kamal so that Amal gets at least 1 pen, Bimal gets at least 2 pens, and Kamal gets at least 3 pens?

What is the divisibility rule of 2 and 3?

Important divisibility rule of:- 2 = last number should be multiple of 2. 3 = sum of digits should be divisible by 3. 4 = last 2 digits should be multiple of 4.