Guidelines

How many ways are there to line up the five people if A is somewhere after B although not necessarily immediately after?

How many ways are there to line up the five people if A is somewhere after B although not necessarily immediately after?

(read as “5 factorial”[2]) = 120 different ways to line up those 5 people.

How many ways can combination be arranged?

4,989,600 different ways
The letters in the word ‘combination’ can be arranged 4,989,600 different ways! This is how you can calculate this answer: There are 11 letters in…

How many ways can 6 students be lined up in a row for a photograph?

EXAMPLE 2: How many ways can you line up 6 students? 720. There are 6 choices for the first position, 5 for the second, 4 for the third, 3 for the fourth, 2 for the fifth, and 1 for the sixth.

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How many ways can you arrange 5 people in a lineup?

Answer: If the symmetry of the table is not taken into account the number of possibilities is 5! = 120. In this case it would be the same as ordering people on a line. However if rotation symmetry is taken into account, there are five ways for people to sit at the table which are just rotations of each other.

What will be the number of ways to arrange 10 elements out of which 6 are repeated?

720What will be the number of ways to arrange 10 elements out of which 6 are repeated.

How many ways can you re-arrange 3 people in a sentence?

Well, we have 3 choices for the first person, 2 for the second, and only 1 for the last. So we have 3 ∗ 2 ∗ 1 ways to re-arrange 3 people.

How many ways can you arrange the friends around the table?

Solution 1: Since rotations are considered the same, we may fix the position of one of the friends, and then proceed to arrange the 5 remaining friends clockwise around him. Thus, there are 5! = 120 5! = 120 ways to arrange the friends. 6! 6! 6! ways to seat the 6 friends around the table.

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How many ways can 6 people be seated around a round table?

Since seat A can be filled only by one person ( first person, our reference), seat B can be occupied by any of the remaining 5 ( anyone but first person who already occupied A), seat C can be occupied by any of the remaining 4 and so on.. So the number of ways 6 people can be seated around a round table becomes 1x5x4x3x2x1=120.

How many ways can you make 6 people sit on 6 chairs?

Now our aim is to arrange the remaining 5 persons on the seats from B to F. If the question was to find the number of ways of making six people sit on six chairs, the answer would have been 6! which is equal to 6x5x4x3x2x1=720.