How many ways can a party of 4 men and 4 women be seated at a circular table so that no two women are adjacent?

of ways = 6 × 24 = 144 ways.

How many ways are there to seat four men and four women in a row if none of the men are seated next to each other?

There are 3 options for the fourth seat too, then 2 options for each of the next two and just 1 option for each of the final two (the one remaining person from each gender). We therefore have to multiply 8*4*3*3*2*2*1*1=1,152 ways in total.

How many ways can 6 women and 6 men be seated in a circular table such that no two women are adjacent to each other?

this being the case it sets up the same problem where six men sit at one table and six women at a second table. In each case the men and women each can be seated in 6 factorial ways, 6x5x4x3x2x1, which is 720 ways for the men and 720 ways for the women. This totals 1440 possible combinations.

How many ways can 6 men and 6 women be seated in a row?

Let us assume the women are seated first. Then the women can be arranged in 6! =720. ways.

How many ways can a party of 4 men and 4 women?

4P4=4! =24 ways. ∴ the required number of ways =(6×24)=144.

How many ways can 3 men and 4 women be seated?

Now there are 4 places between the men and three women are to be seated between the men. That can be done in 4P3 ways. Again you get 144 arrangements.

How many ways are there for four men and five women to stand in a line so that a all men stand together?

ways therefore 720 x 24 =17280 ways.

How many ways 4 men and 3 women are arranged at a round table if the women always sit together?

Therefore total number of ways is equal to 24 × 6 = 144 ways .

How many ways 5 Indians and 4 Americans be seated around the table if no two Americans sit together?

The number of ways in which both sit together = ( 5! × 4! ) Now, The number of ways in which American are not together = 9!

How many ways can 4 men and 4 women sit in a circular table?

How many ways can men and women sit at one table?

this being the case it sets up the same problem where six men sit at one table and six women at a second table. In each case the men and women each can be seated in 6 factorial ways, 6x5x4x3x2x1, which is 720 ways for the men and 720 ways for the women.

How many women can be seated at the circular table?

The 4 men can be seated at the circular table such that there is a vacant seat between every pair of women. 3! = 6. 3! = 6. 3! = 6. Now the 4 vacant seats can be occupied by the women in

How many ways can you seat 6 men and 6 women?

Therefore the total of ways to seat 6 men and 6 women such that no men sit together = 2* (6!) (5!) = 172,800. If there were to be no constraints regarding the seating of 6 men and 6 women the permutations of occupying 12 chairs in a circular arrangement would be 11!=39,916,800.

How many people can be seated in a 4-person group?

Now we have we 4 people(1 men group, 1 women group, 2 men or women) they can be seated in 4! ways. Now each of the group of men and women can swap places within themselves so we should multiply the answer with 4!*4!