How many ways can a photographer Arrange 6 people in a row?

The number of ways you can arrange 6 people is 6! = 720.

How many ways can a party of 7 persons arrange themselves in a row of 7 chains?

So there are 5040 ways of arranging seven people in a row of seven chairs.

How many ways can a photographer in a wedding Arrange 6 people in a row from a groupof 10 people where the bride and the groom are among these 10 people if?

Assuming my reasoning is correct in both a) and b), the number of combinations of 6 people from a group of 10 where either the bride or the groom (but not both) is chosen is just 1×8×7×6×5×4=40,320 for the bride and for the groom.

How many different batting orders can a manager make with his starting team of 9 players?

362,880
A baseball team has 9 starting players. How many ways can the coach make out the batting order? 9! = 9 · 8 · 7 · 6 · 5 ·4 · 3 · 2 · 1 = 362,880 .

How many ways can 9 children line up?

Unlock Overall, it looks like 9x8x7x6x5x4x3x2x1, or 362,880 ways of arranging the people.

How many ways can you arrange 6 people?

The number of ways you can arrange 6 people is 6! = 720. Now, we need to count the invalid combinations. There are five places to put the couple, two ways to order them, and 4! ways to place the four other people. That makes 5*2*4! = 240.

How many permutations are there in a row of 7 chairs?

You can put this solution on YOUR website! In a row of 7 chairs, the number of permutations would be 7!. around a circular table it becomes a little more complicated. this is because there is no fixed first chair. it could be any one of the 7.

How many ways can you fill the 5th place?

There are 5 people to fill the first place, 4 remaining to fill the second, 3 remaining to fill the third, 2 remaining to the fourth place and only 1 remaining to fill the fifth. That means there are 5 factorial (5!) ways. 5! = 5 x 4 x 3 x 2 x 1 = 120.

How many positions does the first person have to choose from?

The first person has 5 positions to “choose” from. The second person then has 4 positions that remain available to choose from, since the first person is now occupying a position. The third person then has 3 choices, the fourth has 2, and finally the fifth and last person has only one place left to choose.