How many ways can a student answer 6 out of 10 questions?

200 ways
of different possible ways the student can choose 6 questions are. ⇒ (5 × 10) + (10 × 10) + (10 × 5) = 200 ways.

How many choices should a student have if they attempt 6 out of 10?

R D Sharma – Mathematics 9 Number of ways to attempt more than 4 from each group. Hence, our required ways = 200.

How many ways can a committee of be selected from a club with members?

There are 252 ways to select a committee of five members from a group of 10 people.

How many ways you can answer one or more questions out of 6 questions each having an alternative?

The number of ways an examiner can answer one or more questions is. 720.

How many ways can you select a committee of 5 students?

What is the value of 5 square into 25 power 8?

Answer: Value of given expression is 625.

How many questions does a student have to answer in exams?

A student has to answer 8 out of 10 questions in an examination. How many choices does the student have if the first 3 questions must be answered? Question:A student has to answer 8 out of 10 questions in an examination.

How many ways can you choose 8 of the 10 questions?

Since the first 3 questions must be answered, there are ( 7 2) = 21 choices for the 2 questions that aren’t answered, so there are 21 ways to choose 8 of the 10 questions if your choice is required to include the first 3 questions.

How many questions do you need to answer in Stack Exchange?

The first three questions must be answered so there is no choices there. The other five questions must be picked from the remaining seven problems. Now you can figure out the correct answer. Thanks for contributing an answer to Mathematics Stack Exchange! Please be sure to answer the question. Provide details and share your research! But avoid …

How many ways can you answer 4 of the remaining 7?

Now, for the minimum requirement of 4 questions answered of the remaining 7 questions. This can be written (we now know) as 7C4, which is the same as 7! / (4! x 3!). 5040 / (24 x 6) = 35. So there are 35 possible combinations of ways to answer 4 of the remaining 7 questions. .