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How many ways can five distinct letters be placed in 5 distinct envelopes such that exactly one letter is placed inside a wrong envelope?

How many ways can five distinct letters be placed in 5 distinct envelopes such that exactly one letter is placed inside a wrong envelope?

There is a total of 5! = 5x4x3x2x1 = 120 possible combinations. Hence, as there is only one way of defying the statement that at least one letter is put into the wrong envelope, the number of combinations which at least one of the letter is put in the wrong envelope is 120–1=119.

What is the probability that none of the letters are inserted into correct envelope?

The probability that no letter mailed in its correct envelope is 3/8.

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Can you put two letters one envelope?

For a 70 cent letter, put on a 55 cent (or forever stamp) and a 15 cent stamp (or “additional ounce” stamp), or another combination that adds up to the same 70 cents. Generally speaking, you can mail 4-5 pages of regular paper, plus an envelope, for the regular first class (“one stamp”) rate.

What is the probability that at least one of the envelope has the right card inside?

In 4 out of 6 combinations, there is at least one letter in the correct envelope. Hence the probability of having at least one letter in the correct envelope is 46.

How many letters does the Secretary type in each envelope?

A secretary types three letters and the three corresponding envelopes. In a hurry, he places at random one letter in each envelope. What is the probability that at least one letter is in the correct

How many ways can 5 letters be put in 5 addressed envelopes?

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The number of ways in which 5 letters can be put in 5 addressed envelops such that not a single letter goes into its correct addressed envelope is- (d)45.

How many ways can a letter not go in the envelope?

We have to find the number of ways in which no letter goes in the envelope having the same number as its number. There are 4 ways for the first letter to go in an envelope other than the 1st one. Let us assume, for definiteness, that the letter 1 gets put in envelope 3.

What is the probability of at least one letter in the correct envelope?

$231:$ no letter is in the correct envelope $312:$ no letter is in the correct envelope $321:$ letter #$2$ is in the correct envelope In $4$ out of $6$ combinations, there is at least one letter in the correct envelope. Hence the probability of having at least one letter in the correct envelope is $\\dfrac{4}{6}$. Share Cite Follow