How many ways can two letters be selected?

Thus, of the 30 permutations of 2 letters from select, only 30–9 = 21 are distinct. In response to the question, there are 21 distinct ways (permutations) of arrangement.

How many different ways can you arrange two letters from the word math?

There are 24 different ways to arrage the letters in the word math .

How many different ways can you rearrange the letters in Mississippi?

34650 so there are 34650 unique ways to arrange the letters in Mississippi. I’ve only just learned this in school myself but I hope it helps! Hi ! I hope you doing well.

How many ways can you arrange the letters school?

360 arrangements
∴ 360 arrangements can be made using the letters of the word SCHOOL.

What does nCr mean math?

nCr means if you are given “n” number different items and you have to chose “r” number of items from it, then nCr gives the total number of ways possible. Mathematically it can be written as n!/r!( n-r)!

How many ways can two a’s be arranged in a word?

In a word ALGEBRA have 2 A’s and 5 different letters are there. 1) Two A’s will take 1 unit and 5 letters will take 5 units then total number units = 6. These can be arranged in 6! = 6x5x4x3x2x1 = 720 ways. 2) The number of arrangements in which two A’s together is = 720 ways.

What is the total number of possible arrangements of three letters?

The second space can be filled by any of the remaining 3 letters. The third space can be filled by any of the 2 remaining letters and the final space must be filled by the one remaining letter. The total number of possible arrangements is therefore 4 × 3 × 2 × 1 = 4!

How do you find the number of ways to arrange an object?

Arranging Objects. The number of ways of arranging n unlike objects in a line is n! (pronounced ‘n factorial’). n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1. Example. How many different ways can the letters P, Q, R, S be arranged? The answer is 4! = 24. This is because there are four spaces to be filled: _, _, _, _

How many ways can you arrange 6x5x4x3x2x1?

These can be arranged in 6! = 6x5x4x3x2x1 = 720 ways. 2) The number of arrangements in which two A’s together is = 720 ways. The number of arrangements with out any restriction = 7! / 2! = 2520 ways. The required number of arrangements if two A’s are not together = 2520 – 720 = 1800 ways.