Under what condition does y1 y2 y3 Do points?

10. Under what condition on y1, y2, y3 do the points (0,y1), (1,y2), (2,y3) lie on a straight line? Solution: The points (0,y1), (1,y2), and (2,y3) will lie on the same line if and only if the slope of the line segment from (0,y1) to (1,y2) is the same as the slope of the line segment from (1,y2) to (2,y3).

What is the sum of 12 5i and 3 4i 16 63i 9 I?

-16 + 63i, 9 – i, 9 – 9i, 15 – 9i. The sum of real numbers and imaginary numbers is called complex numbers. It is in the form a + bi where a is a real number and b is an imaginary part. Therefore, the sum of 12 – 5i and -3 + 4i is 9 – i.

For which triples y1 y2 y3 Does the system Ax y have a solution?

For which triples (y1,y2,y3) does AX = Y have a solution? (y1 – 8y2 – 5y3)   . Therefore, a general solution to this system is given by (x1,x2,x3)=(- 1 2 (y1 -2y2 -y3),- 1 6 (y1 -2y2 +y3), 1 6 (y1 -8y2 -5y3)) .

Which system is independent and inconsistent?

If a consistent system has exactly one solution, it is independent . If a consistent system has an infinite number of solutions, it is dependent . When you graph the equations, both equations represent the same line. If a system has no solution, it is said to be inconsistent .

What is the domain of (x2 – 16)?

Domain for a function means the value/s of x for which the function is valid. In this case, the function is invalid if (x2 − 16) is < 0 as there are no real values of the function. So, you find the values of x which would make (x2 − 16) greater or equal to 0 as the function would be valid.

How do you find the domain of the square root function?

The basic rule to find the domain is simple.Check under what conditions we get a meaningful function value. In (1). From the context it is clear that we are talking about real valued functions. We know the square root of negative numbers are not real. Hence x − 3 ≥ 0 ie x ≥ 3 is the domain. ie Domain = { x ∈ R | x ≥ 3 }.

What is the domain of the function g(x)?

The domain of g(x) is x ∈ R − { −4,4}. As you cannot divide by 0, the denominator is ≠ 0 First factor the denominator since (x2 − 16) is the difference of squares: For most functions, the domain is ( − ∞,∞), the set of all reals.