Under what conditions of current do scalar and vector magnetic potential are applied?

Most recent answer The scalar potential can be used when the field is curl free. That is, for the magnetic field (whose rotational is equal to the current, according to Ampere’s Law) the scalar potential can only be used in regions without current. The potential vector can be used in all regions.

What if magnetic monopoles exist?

A magnetic monopole, if it exists, would have the defining property of producing a magnetic field whose monopole term is non-zero. A magnetic dipole is something whose magnetic field is predominantly or exactly described by the magnetic dipole term of the multipole expansion.

Why magnetic monopoles does not exist explain?

A magnetic monopole does not exist. Just as the two faces of a current loop cannot be physically separated, magnetic North pole and the South pole can never be separated even on breaking a magnet to its atomic size. A magnetic field is produced by an electric field and not by a monopole.

Why is magnetic potential considered a vector quantity?

Magnetic fields can be written as the gradient of magnetic scalar potential. It helps to visualize the strength and direction of the magnetic field. It is a vector field. So electric fields and magnetic fields are vector quantities.

Why magnetic potential is A vector quantity?

Is magnetic moment is a scalar quantity?

Is magnetic moment scalar or vector? The magnetic moment is a vector quantity.

What is magnetic vector potential A vector?

Magnetic vector potential, A, is the vector quantity in classical electromagnetism defined so that its curl is equal to the magnetic field: . Together with the electric potential φ, the magnetic vector potential can be used to specify the electric field E as well.

What is the scalar magnetic potential?

The Scalar Magnetic Potential The vector potential Adescribes magnetic fields that possess curl wherever there is a current density J(r). In the space free of current, and thus Hought to be derivable there from the gradient of a potential. Because we further have The potential obeys Laplace’s equation.

Why do we use vector potentials in physics?

In some branches of physics, especially electrodynamics, it is convenient to introduce a vector potential A such that a (force) field B is given by An obvious reason for introducing A is that it causes B to be solenoidal; if B is the magnetic induction field, this property is required by Maxwell’s equations.

When B is solenoidal a vector potential exists?

An obvious reason for introducing A is that it causes B to be solenoidal; if B is the magnetic induction field, this property is required by Maxwell’s equations. Here we want to develop a converse, namely to show that when B is solenoidal, a vector potential A exists.

How do you find potentials from Maxwell’s equations?

If we introduce suitably defined scalar and vector potentials φ and A into Maxwell’s equations, we can obtain equations giving these potentials in terms of the sources of the electromagnetic field (charges and currents). We start with B = ∇ × A, thereby assuring satisfaction of the Maxwell’s equation ∇ ⋅ B = 0.