What is the apparent weight of the person when the elevator is freely accelerating downwards?

(iv) When the lift falls freely. R = m(g – g) = 0. Thus, the apparent weight of the man becomes zero. This is because both the man and the lift are moving downwards with same acceleration ‘g’ and so there are no forces of action and reaction between the person and the lift.

When a person stands on a scale in an accelerating elevator what kind of force is the scale reading?

The scale reads the Normal force, so it reports your weight as greater than it was at rest. The same two forces are at work as when the elevator was accelerating up. The scale will read the Normal force which is less than it was at rest.

What is the apparent weight of elevator in N and M?

“N” is the apparent weight of passenger (the reading on the scale), and “mg” is actual weight of passenger. So apparent weight of passenger is given by: And the apparent weight of elevator is equal to “T”.

What happens when an elevator is moving at a constant velocity?

The same is true when the elevator is moving at a constant velocity. There elevator is in equilibrium. You may notice that when the elevator begins to move, your weight seems to change. As the elevator begins to rise, you feel heavier. When the elevator descends, you feel lighter.

What happens when you and your scale are in motion?

When you and the scale are stationary with respect to each other, these forces balance out and your weight is equal to the Normal force. What if you and your scale are in motion, like in an elevator? If the elevator is stopped, the scale reads what you would expect it to read, your weight in an elevator.

What happens to your weight when you ride in an elevator?

You may notice that when the elevator begins to move, your weight seems to change. As the elevator begins to rise, you feel heavier. When the elevator descends, you feel lighter. Let’s see why this happens.