What is the change in the area of a rectangle when its length increases by 10\% and its width decreases by 10 \%?

Area of a rectangle = length × width = 100 × 100 = 10,000 sq units. The length increases by 10\%; the new length will be 100 + 10\% of 100 = 110 units. The width decreases by 10\%; the new width will be 100 – 10\% of 100 = 90 units. Therefore, new area = 110 × 90 = 9900 sq units.

What is change in area of rectangle?

Since the area of the rectangle is given by the formula: area = length * breadth. Let the initial length of the rectangle be L and the breadth of the rectangle be B. Therefore, the initial area is given by L * B. Therefore, the new length and breadth are given as: L’ = L + ((P/100)*L) B’ = B + ((Q/100)*B)

Which number is 60\% less than 80?

From the above calculations, we have got the number 32 which is $ 60\\% $ less than 80.

What is the percent increase in length of the rectangle?

The length of a rectangle is increased by 10\%. By what percent breadth of the rectangle must be reduced so that area of the rectangle remains unchanged? – Competoid.com The length of a rectangle is increased by 10\%. By what percent breadth of the rectangle must be reduced so that area of the rectangle remains unchanged?

What is the area decreased by 10\% when length increases?

For area to remain same ΔA/A should be equal to zero. (Given length increases by 10\%, that means x = 0.1) Given that, area is same in both case. therefore, approx 9\% of breadth is decreased to constant the area. How did this girl break the private jet industry with just $250?

What is the 12\% change in area from 10\% to 20\%?

Now as the lenght is increased by 10\% so new lenght will be 22 , and corresponding change in area will be= ( 200–24 ) where 24 is the 12\% decrese in 200. Let the change in bredth be “x” . As 2 being the 20\% change in 10, we can conclude that the breadth should be decreased by 20\% to attain the 12\% change in area.

What is the net percent change in width to Kep area constant?

Increase in length by 10\% or 1/10th ,will require 1/ (10 + 1 ) or 9 1/11\% decrease in width to kep area constant. This is a rule worth remembering. Net percentage change if two variables are multiplied together is given by : Increase in length by 10\% or 1/10th ,will require 1/ (10 + 1 ) or 9 1/11\% decrease in width to kep area constant.