What is the equation of the line that passes through the point 1 4?

The equation of the line is y=3x+1 .

What is the equation of a line passing through the x axis at (- 1 0 and Yaxis at 0 4 )?

Example: Intercepts from a table. We’re given a table of values and told that the relationship between x and y is linear. Then we’re asked to find the intercepts of the corresponding graph. The key is realizing that the x-intercept is the point where y = 0 y=0 y=0 , and the y-intercept is where x = 0 x=0 x=0 .

How do you find the equation of a line through a point?

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

What is the equation of line of x-axis?

The equation of the x-axis is given by y = 0. The equation of the line parallel to the x-axis is y = k, where ‘k’ is any real number. For example, considering the equation of a line, y = 2, for any value of ‘x’ the value of ‘y’ is always equal to 2.

What is the equation of the x-axis?

The equation of the x-axis is x=0.

How do you find a line that passes through two points?

Hence, we are required to find a line passing through two known points that are (1, 4) & (0, -5) and it is therefore given by ; y -9x + 5 = 0 . Line x – 2y – 10 = 0 and y = mx + c intersect on Y-axis, hence put x = 0, in both equations to get y = –5 and y = c. So c = –5 Now, this line passes through (1,4), so this point will satisfy the equation.

Which point is required for x – 2y – 10 to intersect?

Since the required line is intersecting the line x – 2y -10 = 0 at y- axis therefore this point is obtained by putting x = 0 (y-axis) in this equation and it gives y = – 5 that is required point is (0, -5) . Hence, we are required to find a line passing through two known points that are (1, 4) & (0, -5) and it is therefore given by ;

What happens when a line is parallel to the Y-axis?

A line that is parallel to the y-axis cannot, anywhere along its length, change it’s value for x. Parallel lines are always the same distance apart. If the lines tended toward each other, down one extent, then (because they are straight), the lines will eventually touch and cross.

How to find the slope of a line with one point?

Let m1 be the slope of the given line and m2 slope of the equation of the line to be found. Slope of the given line is -3/4. So, -3/4×m2=-1, m2= 4/3. Now we know the slope of the line and one point is given, by applying the formula, y-y1=m (x-x1) 4 x − 3 y + 1 = 0.