What is the molarity of a solution containing 23 g of NaCl in 500 mL of solution the molar mass of NaCl is 58.44 g?

What is the molarity of a solution containing 23 g of NaCl in 500 mL of solution? Molarity is number of moles of solute in unit volume for this solution. 1 mole of NaCl weight 58.5 g, so, we have 23/(58.5 )=0.393 moles in 500 mL. In 1 L is 0.393*2 =0.786 moles, so, molarity is 0.786 moles/L or 0.786 M.

How do you calculate the molarity of a NaCl solution?

To get the molarity we need to divide the number of moles of NaCl by the volume of the solution. In this case that is 0.32 moles NaCl divided by 3.4 L, and that gives 0.094 M NaCl.

What is the molarity of a solution that contains 58.5 g of sodium chloride dissolved in 0.500 l of solution?

What is the molarity of a solution which contains 58.5 g of sodium chloride dissolved in . 500 L of solution? Molarity=moles/volume, 58.5 g of NaCl equals 1 mole, so Molarity=1/. 5, which is 2.

What will be the molarity of a solution which contains 5.85 g of NaCl per 100ml?

0.2 mol L^-1.

What is the molarity when 58.4 g of NaCl is dissolved in 500ml of solution?

When we dissolve 5.85g of NaCl in 500 ml of water then the molarity of the NaC l is 0.2M.

What is the molarity of a solution that contains 234 g HCl in 2.90 L solution?

5. A solution consists of 0.50 mole of Caci: dissolved in 100.

What is the molarity of NaCl?

One mole of sodium (Na) is 22.99 g, and 1 mole of chlorine is 35.45 g. For sodium chloride (NaCl) they are in a ratio of 1:1 so the molar mass of NaCl is 22.99 + 35.45 = 58.44 g/mol.

What is the molarity of a solution which contains 58.5 g of NaCl?

The molarity of a solution is defined as the number of moles of a solute dissolved in 1 litre of a solution. The given solute is NaCl and its molar mass is 58.44 ~ 58.5 g. Therefore, a 1M solution of NaCl will contain 58.5g of NaCl dissolved in 1 litre of solvent. = = 0.1/0.5 = 0.2M or 0.2 mol L-1.

What is the molarity of a solution which contains 58.5 g of NaCl per 500ml?

Molarity = 0.01/0.5=0.02 mol per litre.

What will be molarity of solution?

The molarity (M) of a solution is the number of moles of solute dissolved in one liter of solution. To calculate the molarity of a solution, you divide the moles of solute by the volume of the solution expressed in liters. When a molarity is reported, the unit is the symbol M and is read as “molar”.

What is the molarity of a solution which contains 58.4 g of sodium chloride?

Calculating Molarity Given Moles and Volume We do this by dividing by the molecular weight of NaCl (58.4 g/mole). Then, we divide the number of moles by the total solution volume to get concentration. The NaCl solution is a 0.1 M solution.

How do you find the molarity of a solution with water?

This example is prepared with “enough water” to make 750 mL of solution. Convert 750 mL to liters. This is enough to calculate the molarity. The molarity of this solution is 0.20 M (moles per liter). Divide moles solute by liters solution.

How do you find the molarity of KMnO4 solution?

Calculate the molarity of a solution prepared by dissolving 23.7 grams of KMnO 4 into enough water to make 750 mL of solution. This example has neither the moles nor liters needed to find molarity, so you must find the number of moles of the solute first.

How do you calculate liters of solution from 1 mol of NaOH?

Solution: 1 mol of NaOH has a mass of 40.00 g, so. #”Moles of NaOH” = 15.0 cancel(“g NaOH”) × “1 mol NaOH”/(40.00 cancel(“g NaOH”)) = “0.375 mol NaOH”#. #”Litres of solution” = 225 cancel(“mL soln”) × “1 L soln”/(1000 cancel(“mL soln”)) = “0.225 L soln”#.

What is the molecular weight of NaCl in molar solution?

Questions. The molecular weight of NaCl is 58.44 grams/mole. If you had a 1.0 molar solution (1.0 M), you would have to put 58.44 g of salt in 1.0 liter of solution.