What is the path of a charged particle in a uniform magnetic field if its velocity is not perpendicular to the magnetic field?

If a charged particle moves in a region of a uniform magnetic field such that its velocity is not perpendicular to the magnetic field, then the velocity of the particle is split up into two components. One component is parallel to the field while the other component perpendicular to the field.

What will be the path of a charged particle moving in a uniform magnetic field at an arbitrary angle?

“It will go along straight path in Uniform Magnetic Field.” The motion of charged particle is same as that of magnetic field i.e angle b/w them is 0°.

How electric field E magnetic field B and velocity v are related in terms of magnitude?

v=B2/E.

How do you find the path of a particle?

To find equation of trajectory of a particle, find first x and y co-ordinates of the particle as a function of time and eliminate the time factor. The position vector of car w.r.t. its starting point is given as r =ati^−bt2j^​ where a and b are positive constants. The locus of a particle is.

What is the path of a charged particle moving in a uniform electric field?

(ii) When a charged particle moves perpendicular to both electric and magnetic fields, then due to electric field, the charged particle describes a parabolic path the due to magnetic field, it will describe a circular path. As a result of it, the particle will follow a resultant path in electric and magnetic fields.

What is the path of a charged particle moving along the uniform electric field?

Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle.

What is the path of the charged particle moving along the uniform electric field?

When a charged particle moving with a velocity v is subjected to a magnetic field B the force on it is non zero this implies that *?

Its direction is perpendicular to direction of motion of particle as well as perpendicular to the direction of magnetic field. Due to it, no work is done by the magnetic force on the charged particle. Therefore, the particle does not gain any kinetic energy.

When a charged particle enters a magnetic field what is its kinetic energy?

when a charged particle enters a uniform magnetic field , its kinetic energy remains constant. The magnetic field always exerts a force perpendicular to the particle’s velocity, so the magnitude of the velocity remains constant and so does the kinetic energy.

What happens when a charged particle moves in an electric field?

The motion of a charged particle in the electric and magnetic field In case of motion of a charge in a magnetic field, the magnetic force is perpendicular to the velocity of the particle. So no work is done and no change in the magnitude of the velocity is produced (though the direction of momentum may be changed).

Why does a particle move in the y direction?

The motion in a plane perpendicular to B is as before a circular one, thereby producing a helical motion. However, the electric field in y-direction imparts acceleration in that direction. The particle, therefore, acquires velocity in the y-direction and resulting motion is a helical motion.

What is the path of a particle moving in a magnetic field?

If there is a component of the velocity parallel to the magnetic field (denoted by v 2 ), it will make the particle move along both the field and the path of the particle would be a helical one. The distance moved along the magnetic field in one rotation is called pitch p. Learn more about Domestic Electric Circuits.

What happens when a charged particle travels in a helical path?

While the charged particle travels in a helical path, it may enter a region where the magnetic field is not uniform. In particular, suppose a particle travels from a region of strong magnetic field to a region of weaker field, then back to a region of stronger field. The particle may reflect back before entering the stronger magnetic field region.