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What is the sum of the first 7 terms of a geometric sequence 3 6 12?

What is the sum of the first 7 terms of a geometric sequence 3 6 12?

Hence, the value of the sum of the first 7 terms is 381.

How do you find the sum of the first 7 terms of the geometric sequence?

The formula is given by Sn=a(1−rn1−r) where a is the first term of the series, r=arn−1arn−2 and Sn is the sum of the first n terms. Hence, the value of the sum of the first 7 terms is 6096. Note: The formula for finding the sum of G.P.

What is the sum of the first seven terms in a geometric sequence?

16383
3 + 12 + 48 + 192 + … Summary: The sum of the first seven terms of the given GP series is 16383.

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How do you find the sum of the terms of a geometric sequence?

Starts here3:43Geometric Series (How to Find the Sum of a Sequence) – YouTubeYouTube

What is the sum of first 5 terms of the geometric series?

The formula to find the sum of first 5 terms of the geometric series is, Sn = a(rn – 1) r – 1 So, S5 = 1(25 – 1) 2 – 1 S5 = 1 (32 – 1) 1

How do you find the sum of the first 7 terms?

The formula to find the sum of the first 7 terms of the geometric series is, Sn = a(rn – 1) r – 1 ⇒ S7 = 1(27 – 1) 2 – 1 ⇒ S7 = 1 (128 – 1) 1

How do you find R in a geometric series?

A geometric series is a set of numbers where each term after the first is found by multiplying or dividing the previous term by a fixed number. The common ratio, abbreviated as r, is the constant amount. Let the first, second, third, … …, n t h term be denoted by T 1, T 2, T 3, …. T n, then we can write, ⇒ r = T n T n – 1.

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How do you find the common ratio of a geometric progression?

Find the common ratio and the terms. Three distinct numbers, x, y, z form a geometric progression in that order, and the numbers x + y, y + z, z + x form an arithmetic progression in that order. Find the common ratio of the geometric progression. The first term of a G.P. is 1. The sum of the third term and fifth term is 9 0.