When a lift moves up with a constant velocity the apparent weight is?

From the above explanation and given condition when person in an elevator is moving at constant speed in such case the net acceleration will be zero. Thus we can say that person’s weight when he is in a moving elevator will not change because the apparent weight of the person will be equal to its true weight.

What is lift equal to when an object is lifted at a constant speed?

When an object is lifted or projected upward, work must be done against the resistance from gravity, inertia and air resistance. If the object is moving upward at constant velocity, the work done by gravity is simply the force of gravity times the displacement.

What is the apparent weight of a person when an elevator is accelerating upwards?

When a lift is going up with uniform acceleration, the apparent weight of a person is W1​ When the lift is stationary, his apparent weight is W2​

What is the apparent weight of the man of mass m when the lift is moving up with uniform speed?

Explanation: Since it is moving with uniform speed, there no additional force (a = 0) So, apparent weight = m(g + 0) = (60 kg) × (10 ms-2 ) = 600 N.

What will be the apparent weight of the object when the lift moves with a constant speed v downwards?

Now, since question says that lift is moving with constant velocity v , the value of “a” = 0 m/s². So, apparent weight will be equal to weight of the body.

Can a lift move with constant velocity?

Yes it will go up with uniform velocity if the tension force is equal to the force of gravity given that it already has an upward velocity.

What two forces act on you in a moving elevator?

The two forces acting on a person when he is moving in an elevator is the force of gravity and the normal force by the elevator. The two forces are of equal magnitude, and the elevator is static or moving with constant velocity. Their magnitudes are unequal when the elevator is accelerating upward or downward.

When a person lifts an object at constant velocity the kinetic energy is?

At constant velocity, there is no change in kinetic energy, so the net work done to move the car is zero.

What force is used to lift?

The weight is the force by which the earth is attracting the object. In order to lift the object, a net upward force is required. This is possible only if the upward force is greater than the weight.

What is the apparent weight of a man in a lift?

zero
When the lift free falls below due to gravity. Then a =g. And the man’s apparent weight gets zero.

What is the apparent weight of man in a lift when he is moving downwards?

R = m(g – g) = 0. Thus, the apparent weight of the man becomes zero. This is because both the man and the lift are moving downwards with same acceleration ‘g’ and so there are no forces of action and reaction between the person and the lift.

Why is the total work done by a man on lift zero?

If a man is standing on a lift which is moving with constant velocity it exerts a force but the total workdone is constant or zero. This is because the displacement of lift is not due to the weight of the man but due to the mechanism of the lift.

What happens when an elevator is moving at a constant velocity?

The same is true when the elevator is moving at a constant velocity. There elevator is in equilibrium. You may notice that when the elevator begins to move, your weight seems to change. As the elevator begins to rise, you feel heavier. When the elevator descends, you feel lighter.

What is the normal force on the shoes in the elevator?

And Newton’s first law tells there’s no net force on this. So it’s just like the first situation. The normal force, the force of the elevator on this toddler’s shoes, is going to be identical to the downward force due to gravity. So the normal force here is going to be 98 newtons.

What is the normal force in the J direction?

So that net force in this situation is the force of the floor of the elevator supporting the toddler. So that force would be an equal force but in the opposite direction. And in this case, that would be the normal force. So in this case, the normal force is 98 newtons in the j direction.