When an empty lift is moving down with an acceleration of G by 4 Metre per second square the tension in the cable is 9000 newton?

Therefore, Therefore, the Tension in the cable at the time of the ascend is 16000 Newtons.

What happens to the body kept in a lift moving down with acceleration a G?

So, when a lift accelerates downwards, the apparent weight of the person inside it decreases. R = m(g – g) = 0. Thus, the apparent weight of the man becomes zero.

When the lift is moving downwards?

A lift is moving downwards with an acceleration equal to the acceleration due to gravity. A body of mass M kept on the floor of the lift is pulled horizontally, if the coefficient of friction is μ, then the frictional resistance offered by the body is.

When a lift moving downwards with an acceleration?

A lift is moving downwards with an acceleration equal to the acceleration due to gravity.

When lift going down with acceleration the apparent weight of a body will?

R = m(g – g) = 0. Thus, the apparent weight of the man becomes zero. This is because both the man and the lift are moving downwards with the same acceleration ‘g’ and so there are no forces of action and reaction between the person and the lift.

What is the acceleration of the lift?

the elevator has no acceleration (standing still or moving with constant velocity) the elevator has an upward acceleration (accelerating upward, or decelerating while on the way down) the elevator has a downward acceleration (accelerating down, or decelerating while on the way up)

When a lift comes downwards with uniform acceleration then mass of the body?

When the lift goes down the weight of the body decreases because when the lift goes down there is a force called pseudo force which pushes lift upward and results in a decrease in weight. So option 2 is correct. When the lift goes up the weight of the body increases.

When lift is accelerating upwards the apparent weight is?

When the lift accelerates upward, a pseudo force will act on the body in the downward direction in addition to the weight. So the apparent weight will increase. If lift is going with uniform speed, the force acting on the body will be weight of the person. So the apparent weight will be same as the real weight.

When the lift moves upwards with a uniform acceleration a the apparent weight of the man is W?

A man in a lift feels an apparent weight W when the lift is moving up with a uniform acceleration of 1/3rd of the acceleration due to gravity. If the same man were in the same lift now moving down with a uniform acceleration that is 1/2 of the acceleration due to gravity, then his apparent weight is.

What is the apparent weight of a person 60 kg moving upward in a lift with a constant speed of 1’m s?

Explanation: Since it is moving with uniform speed, there no additional force (a = 0) So, apparent weight = m(g + 0) = (60 kg) × (10 ms-2 ) = 600 N.

What is the apparent weight of a person 60 kg moving upward in a lift with a constant speed of 1 Metre per second?

Statement B: When the lift is moving with uniform velocity, then the apparent weight of the man is zero.