Which of the following properties must a Group G hold in order to be an Abelian group?

commutative property
The commutative property must hold, in order to be an Abelian group. since group is given so all other property is inclusive.

How many different 3 member committees are possible there must be at least 1 girl?

So 276 combinations of the 336 combinations have at least one woman.

How many property can be held by a group?

So, a group holds five properties simultaneously – i) Closure, ii) Associative, iii) Identity element, iv) Inverse element, v) Commutative.

How many women can be on a committee of 5?

“At least” One Women Selected. Which means we have to calculate for the cases when 1 women is on the committee, when 2 women could be on the committee, 3 women on the committee and all 4 women on the committee. A committee of 5 people is to be chosen from a group of 6 men and 4 women.

How many people are required to be on a committee?

A committee of 5 people is to be chosen from a group of 6 men and 4 women. How many committees are possible if there must be “At least “ One women on the committee?

How many different types of committees are there?

There are 1,176 different possible committees. Let’s break this down into the two sub-groups: one with men, and one with women. Of the 8 men available, we must choose 3. The number of possible groups is 8C3, which is 8! 3! × 5! = 56. Of the 7 women available, we must choose 2. The number of possible groups is 7C2, which is 7! 2! × 5! = 21.

How many possible combinations are there with 56 men and 15 women?

Well, you can form 8 choose 3 groups of men, and for each of those you can choose any of the 6 choose 2 groups of women. nCr=n!/ ( (r!) (n−r)!) So, 56*15=840 possible combinations, assuming you don’t care about anything other than number of men, number of women.