What is the decimal value of 010?
Table of Contents
What is the decimal value of 010?
1.4. 2 Binary Numbers
| 3-Bit Binary Numbers | 4-Bit Binary Numbers | Decimal Equivalents |
|---|---|---|
| 010 | 0010 | 2 |
| 011 | 0011 | 3 |
| 100 | 0100 | 4 |
| 101 | 0101 | 5 |
Is 08 an octal number?
8 is not an octal digit, no more than 2 is valid in binary or G is valid in hexadecimal. In Java, if you are defining an int with a leading ‘0’ denotes that you are defining a number in Octal. int a = 08 is giving out of range error because there is no any number ‘8’ in Octal.
What is the decimal value of integer literal 08?
Answer: A sequence of digits starting with 0 is taken to be an octal integer. For instance, decimal integer 8 will be written as 010 as octal integer and decimal integer 12 will be written as 014 as octal integer.
What are octal numbers in Java?
Octal is a number system where a number is represented in powers of 8. So all the integers can be represented as an octal number. Also, all the digit in an octal number is between 0 and 7. In java, we can store octal numbers by just adding 0 while initializing.
What is the value of 010 integer literal?
8
An octal numeral consists of an ASCII digit 0 followed by one or more of the ASCII digits 0 through 7 interspersed with underscores, and can represent a positive, zero, or negative integer. Now you should understand why 010 is 8 . That is because java takes it as an octal literal and hence produces 12.
What is the octal equivalent of 010?
Octal Numbers
| Decimal Number | 3-bit Binary Number | Octal Number |
|---|---|---|
| 1 | 001 | 1 |
| 2 | 010 | 2 |
| 3 | 011 | 3 |
| 4 | 100 | 4 |
What is an integer literal in Java?
An integer literal is a numeric value(associated with numbers) without any fractional or exponential part. There are 4 types of integer literals in Java: binary (base 2) decimal (base 10) octal (base 8)
How do you represent octal and hexadecimal in Java?
A hexadecimal number is a value in base-16. There are 16 digits, 0-9 and the letters A-F (case does not matter). A-F represent 10-16 . An octal number is a value in base-8, and uses the digits 0-7 .
What is the proper way to write octal value in Java?
Literals with a leading zero are octal literals. Any number prefixed with a 0 is considered octal. Octal numbers can only use digits 0-7, just like decimal can use 0-9, and binary can use 0-1.
What is the value of following integer literal 017?
Because the number is presented out of context there is no real way to determine the base in which it is represented, so two answers are given: if base 10, then the value of 017 is 17, and if base 8 then the value of 017 is 8 + 7 = 15.
Why is 010 equal to 8 in Java?
Now you should understand why 010 is 8. A leading 0 denotes an octal numeric value so the value 010 can be decoded thus: 010 = 1 * 8 1 + 0 * 8 0 = 8 That is because java takes it as an octal literal and hence produces 12. Try System.out.println (10|4) and the result is 14.
How does the compiler get the integer value out of 010?
So the compiler gets the integer value out of the octal representation 010 by converting it to the decimal representation using this algorithm 0*8^0 + 1+8^1 = 10 and then assign j to 10. Remember when you see a constant starting with 0 it’s an integer in octal representation. i.e. 0111 is not 1 hundred and 11 but it’s 1*8^0 + 1*8^1 + 1*8^2.
What is the value of a leading 0 in Java?
A leading 0 denotes an octal numeric value so the value 010 can be decoded thus: 010 = 1 * 8 1 + 0 * 8 0 = 8 That is because java takes it as an octal literal and hence produces 12.
Why is 010 an octal integer literal?
Because this time it is taken as decimal literal. As everybody mentioned here that 010 is an Octal Integer literal . The leading 0 specifies that it is an octal representation . Actual value will be : Applying Bitwise OR on 010 and 4 (considering only the last 4 digits) =>